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Convert Date as given in formation string


What is the difference between String and string in C#?How to return only the Date from a SQL Server DateTime datatypeCase insensitive 'Contains(string)'Compare two dates with JavaScriptWhere can I find documentation on formatting a date in JavaScript?Detecting an “invalid date” Date instance in JavaScriptYYYY-MM-DD format date in shell scriptHow do I get the current date in JavaScript?Calculate difference between two dates (number of days)?How to format a JavaScript date






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








1















I have a function that converts a given date to timestamp. the date format is dynamic. for example (it could be 'dd/MM/yyyy' or 'dd-MM-yyyy' or MM/dd/yyyy).but date format is also passed as an argument in the function. i need to seperate day , month and year for this conversion. how can i separate as given in formation string



 public static double GetTimeStamp(string date, string format)

string[] dateToConvert = date.Split('/');

int year=Int32.Parse(dateToConvert[2]);
int month=Int32.Parse(dateToConvert[1]);
int day=Int32.Parse(dateToConvert[0]);

var baseDate = new DateTime(1970, 01, 01);
var toDate = new DateTime(year, month, day);
var numberOfSeconds = toDate.Subtract(baseDate).TotalSeconds;
return numberOfSeconds;



i am using '/' as a separation character. but i want to separate it as provided in the formation. if formation string is (dd-MM-yyyy). i need to seperate it using '-' charecter










share|improve this question

















  • 3





    Have you looked at Datetime.ParseExact? docs.microsoft.com/en-us/dotnet/api/system.datetime.parseexact

    – Flydog57
    Mar 9 at 4:19












  • Yea It works for me. thaks

    – Tanveer Hasan
    Mar 9 at 4:49











  • One other note: you can subtract a DateTime from another DateTime. This will result in a TimeSpan object. That type has a Seconds property. It would simplify your calculation

    – Flydog57
    Mar 9 at 5:18

















1















I have a function that converts a given date to timestamp. the date format is dynamic. for example (it could be 'dd/MM/yyyy' or 'dd-MM-yyyy' or MM/dd/yyyy).but date format is also passed as an argument in the function. i need to seperate day , month and year for this conversion. how can i separate as given in formation string



 public static double GetTimeStamp(string date, string format)

string[] dateToConvert = date.Split('/');

int year=Int32.Parse(dateToConvert[2]);
int month=Int32.Parse(dateToConvert[1]);
int day=Int32.Parse(dateToConvert[0]);

var baseDate = new DateTime(1970, 01, 01);
var toDate = new DateTime(year, month, day);
var numberOfSeconds = toDate.Subtract(baseDate).TotalSeconds;
return numberOfSeconds;



i am using '/' as a separation character. but i want to separate it as provided in the formation. if formation string is (dd-MM-yyyy). i need to seperate it using '-' charecter










share|improve this question

















  • 3





    Have you looked at Datetime.ParseExact? docs.microsoft.com/en-us/dotnet/api/system.datetime.parseexact

    – Flydog57
    Mar 9 at 4:19












  • Yea It works for me. thaks

    – Tanveer Hasan
    Mar 9 at 4:49











  • One other note: you can subtract a DateTime from another DateTime. This will result in a TimeSpan object. That type has a Seconds property. It would simplify your calculation

    – Flydog57
    Mar 9 at 5:18













1












1








1








I have a function that converts a given date to timestamp. the date format is dynamic. for example (it could be 'dd/MM/yyyy' or 'dd-MM-yyyy' or MM/dd/yyyy).but date format is also passed as an argument in the function. i need to seperate day , month and year for this conversion. how can i separate as given in formation string



 public static double GetTimeStamp(string date, string format)

string[] dateToConvert = date.Split('/');

int year=Int32.Parse(dateToConvert[2]);
int month=Int32.Parse(dateToConvert[1]);
int day=Int32.Parse(dateToConvert[0]);

var baseDate = new DateTime(1970, 01, 01);
var toDate = new DateTime(year, month, day);
var numberOfSeconds = toDate.Subtract(baseDate).TotalSeconds;
return numberOfSeconds;



i am using '/' as a separation character. but i want to separate it as provided in the formation. if formation string is (dd-MM-yyyy). i need to seperate it using '-' charecter










share|improve this question














I have a function that converts a given date to timestamp. the date format is dynamic. for example (it could be 'dd/MM/yyyy' or 'dd-MM-yyyy' or MM/dd/yyyy).but date format is also passed as an argument in the function. i need to seperate day , month and year for this conversion. how can i separate as given in formation string



 public static double GetTimeStamp(string date, string format)

string[] dateToConvert = date.Split('/');

int year=Int32.Parse(dateToConvert[2]);
int month=Int32.Parse(dateToConvert[1]);
int day=Int32.Parse(dateToConvert[0]);

var baseDate = new DateTime(1970, 01, 01);
var toDate = new DateTime(year, month, day);
var numberOfSeconds = toDate.Subtract(baseDate).TotalSeconds;
return numberOfSeconds;



i am using '/' as a separation character. but i want to separate it as provided in the formation. if formation string is (dd-MM-yyyy). i need to seperate it using '-' charecter







c# date






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 9 at 4:13









Tanveer HasanTanveer Hasan

667




667







  • 3





    Have you looked at Datetime.ParseExact? docs.microsoft.com/en-us/dotnet/api/system.datetime.parseexact

    – Flydog57
    Mar 9 at 4:19












  • Yea It works for me. thaks

    – Tanveer Hasan
    Mar 9 at 4:49











  • One other note: you can subtract a DateTime from another DateTime. This will result in a TimeSpan object. That type has a Seconds property. It would simplify your calculation

    – Flydog57
    Mar 9 at 5:18












  • 3





    Have you looked at Datetime.ParseExact? docs.microsoft.com/en-us/dotnet/api/system.datetime.parseexact

    – Flydog57
    Mar 9 at 4:19












  • Yea It works for me. thaks

    – Tanveer Hasan
    Mar 9 at 4:49











  • One other note: you can subtract a DateTime from another DateTime. This will result in a TimeSpan object. That type has a Seconds property. It would simplify your calculation

    – Flydog57
    Mar 9 at 5:18







3




3





Have you looked at Datetime.ParseExact? docs.microsoft.com/en-us/dotnet/api/system.datetime.parseexact

– Flydog57
Mar 9 at 4:19






Have you looked at Datetime.ParseExact? docs.microsoft.com/en-us/dotnet/api/system.datetime.parseexact

– Flydog57
Mar 9 at 4:19














Yea It works for me. thaks

– Tanveer Hasan
Mar 9 at 4:49





Yea It works for me. thaks

– Tanveer Hasan
Mar 9 at 4:49













One other note: you can subtract a DateTime from another DateTime. This will result in a TimeSpan object. That type has a Seconds property. It would simplify your calculation

– Flydog57
Mar 9 at 5:18





One other note: you can subtract a DateTime from another DateTime. This will result in a TimeSpan object. That type has a Seconds property. It would simplify your calculation

– Flydog57
Mar 9 at 5:18












1 Answer
1






active

oldest

votes


















0














 DateTime dateTime = DateTime.ParseExact(date, format, null);


int year = dateTime.Year;
int month=dateTime.Month;
int day = dateTime.Day;

var toDate = new DateTime(year, month, day);





share|improve this answer




















  • 1





    To extract the year, month, and day, you can use the relevant properties: int year = dateTime.Year int month = dateTime.Month int day = dateTime.Day This avoids creating strings just to read them back into ints again. To get just the date component you can use: var toDate = dateTime.Date which returns a copy of dateTime with all the time information stripped (set to zero).

    – James
    Mar 9 at 5:02












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1 Answer
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1 Answer
1






active

oldest

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active

oldest

votes






active

oldest

votes









0














 DateTime dateTime = DateTime.ParseExact(date, format, null);


int year = dateTime.Year;
int month=dateTime.Month;
int day = dateTime.Day;

var toDate = new DateTime(year, month, day);





share|improve this answer




















  • 1





    To extract the year, month, and day, you can use the relevant properties: int year = dateTime.Year int month = dateTime.Month int day = dateTime.Day This avoids creating strings just to read them back into ints again. To get just the date component you can use: var toDate = dateTime.Date which returns a copy of dateTime with all the time information stripped (set to zero).

    – James
    Mar 9 at 5:02
















0














 DateTime dateTime = DateTime.ParseExact(date, format, null);


int year = dateTime.Year;
int month=dateTime.Month;
int day = dateTime.Day;

var toDate = new DateTime(year, month, day);





share|improve this answer




















  • 1





    To extract the year, month, and day, you can use the relevant properties: int year = dateTime.Year int month = dateTime.Month int day = dateTime.Day This avoids creating strings just to read them back into ints again. To get just the date component you can use: var toDate = dateTime.Date which returns a copy of dateTime with all the time information stripped (set to zero).

    – James
    Mar 9 at 5:02














0












0








0







 DateTime dateTime = DateTime.ParseExact(date, format, null);


int year = dateTime.Year;
int month=dateTime.Month;
int day = dateTime.Day;

var toDate = new DateTime(year, month, day);





share|improve this answer















 DateTime dateTime = DateTime.ParseExact(date, format, null);


int year = dateTime.Year;
int month=dateTime.Month;
int day = dateTime.Day;

var toDate = new DateTime(year, month, day);






share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 9 at 5:19

























answered Mar 9 at 4:51









Tanveer HasanTanveer Hasan

667




667







  • 1





    To extract the year, month, and day, you can use the relevant properties: int year = dateTime.Year int month = dateTime.Month int day = dateTime.Day This avoids creating strings just to read them back into ints again. To get just the date component you can use: var toDate = dateTime.Date which returns a copy of dateTime with all the time information stripped (set to zero).

    – James
    Mar 9 at 5:02













  • 1





    To extract the year, month, and day, you can use the relevant properties: int year = dateTime.Year int month = dateTime.Month int day = dateTime.Day This avoids creating strings just to read them back into ints again. To get just the date component you can use: var toDate = dateTime.Date which returns a copy of dateTime with all the time information stripped (set to zero).

    – James
    Mar 9 at 5:02








1




1





To extract the year, month, and day, you can use the relevant properties: int year = dateTime.Year int month = dateTime.Month int day = dateTime.Day This avoids creating strings just to read them back into ints again. To get just the date component you can use: var toDate = dateTime.Date which returns a copy of dateTime with all the time information stripped (set to zero).

– James
Mar 9 at 5:02






To extract the year, month, and day, you can use the relevant properties: int year = dateTime.Year int month = dateTime.Month int day = dateTime.Day This avoids creating strings just to read them back into ints again. To get just the date component you can use: var toDate = dateTime.Date which returns a copy of dateTime with all the time information stripped (set to zero).

– James
Mar 9 at 5:02




















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