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How to assign same key to all value in list in python3



2019 Community Moderator Electionwhat is the best way to calculate the power of several ints in a list using python3?append list values to a dictionaryIterating through dictionary with nested lists and printing at board positionSum up the second value from one dictionary with all values from another dictionaryComparing 2 dictionaries in python and create a list with values from dictionaryAppending values to existing keys in a dictionaryPython list-dictionary algorithm with big dataSorting a list based on another shorter list with incomplete valuesPython 3.6. Get average Y for all same X coordinatesBeautifulSoup4 scrapping: Pandas “arrays must all be same length” when exporting data to csv










0















I have two lists with the same length one contains integer values and another string.
a = [4, 8, 13, 24, 35, 56]
b = ['acb','cde','efg','hij','klm','nop']



I want to make dictionary like this:dictionary = 'number':4,'name':'abc', 'number':8,'name':'cde', 'number':13,'name':'efg', 'number':24,'name':'hij', 'number':35,'name':'klm', 'number':56,'name':'nop'

the key should be the same for all the value. Thank in advance










share|improve this question


























    0















    I have two lists with the same length one contains integer values and another string.
    a = [4, 8, 13, 24, 35, 56]
    b = ['acb','cde','efg','hij','klm','nop']



    I want to make dictionary like this:dictionary = 'number':4,'name':'abc', 'number':8,'name':'cde', 'number':13,'name':'efg', 'number':24,'name':'hij', 'number':35,'name':'klm', 'number':56,'name':'nop'

    the key should be the same for all the value. Thank in advance










    share|improve this question
























      0












      0








      0








      I have two lists with the same length one contains integer values and another string.
      a = [4, 8, 13, 24, 35, 56]
      b = ['acb','cde','efg','hij','klm','nop']



      I want to make dictionary like this:dictionary = 'number':4,'name':'abc', 'number':8,'name':'cde', 'number':13,'name':'efg', 'number':24,'name':'hij', 'number':35,'name':'klm', 'number':56,'name':'nop'

      the key should be the same for all the value. Thank in advance










      share|improve this question














      I have two lists with the same length one contains integer values and another string.
      a = [4, 8, 13, 24, 35, 56]
      b = ['acb','cde','efg','hij','klm','nop']



      I want to make dictionary like this:dictionary = 'number':4,'name':'abc', 'number':8,'name':'cde', 'number':13,'name':'efg', 'number':24,'name':'hij', 'number':35,'name':'klm', 'number':56,'name':'nop'

      the key should be the same for all the value. Thank in advance







      python-3.6






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 7 at 7:55









      Manohar SonwanManohar Sonwan

      34




      34






















          1 Answer
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          0














          I'm not sure if this is the method you want, please check the following.



          a = [4, 8, 13, 24, 35, 56]
          b = ['acb','cde','efg','hij','klm','nop']

          c = zip(a,b)
          final_dic = dict()
          for i,a in enumerate(c):
          temp=dict(number=a[0],name=a[1])
          final_dic[i]=temp
          print(final_dic)


          Since the output need to be dictionary format, so I just add the number as the key value.
          I'm also new to Python, so there might be a better to do this.






          share|improve this answer








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            1 Answer
            1






            active

            oldest

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            active

            oldest

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            active

            oldest

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            0














            I'm not sure if this is the method you want, please check the following.



            a = [4, 8, 13, 24, 35, 56]
            b = ['acb','cde','efg','hij','klm','nop']

            c = zip(a,b)
            final_dic = dict()
            for i,a in enumerate(c):
            temp=dict(number=a[0],name=a[1])
            final_dic[i]=temp
            print(final_dic)


            Since the output need to be dictionary format, so I just add the number as the key value.
            I'm also new to Python, so there might be a better to do this.






            share|improve this answer








            New contributor




            Willy Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.
























              0














              I'm not sure if this is the method you want, please check the following.



              a = [4, 8, 13, 24, 35, 56]
              b = ['acb','cde','efg','hij','klm','nop']

              c = zip(a,b)
              final_dic = dict()
              for i,a in enumerate(c):
              temp=dict(number=a[0],name=a[1])
              final_dic[i]=temp
              print(final_dic)


              Since the output need to be dictionary format, so I just add the number as the key value.
              I'm also new to Python, so there might be a better to do this.






              share|improve this answer








              New contributor




              Willy Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.






















                0












                0








                0







                I'm not sure if this is the method you want, please check the following.



                a = [4, 8, 13, 24, 35, 56]
                b = ['acb','cde','efg','hij','klm','nop']

                c = zip(a,b)
                final_dic = dict()
                for i,a in enumerate(c):
                temp=dict(number=a[0],name=a[1])
                final_dic[i]=temp
                print(final_dic)


                Since the output need to be dictionary format, so I just add the number as the key value.
                I'm also new to Python, so there might be a better to do this.






                share|improve this answer








                New contributor




                Willy Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.










                I'm not sure if this is the method you want, please check the following.



                a = [4, 8, 13, 24, 35, 56]
                b = ['acb','cde','efg','hij','klm','nop']

                c = zip(a,b)
                final_dic = dict()
                for i,a in enumerate(c):
                temp=dict(number=a[0],name=a[1])
                final_dic[i]=temp
                print(final_dic)


                Since the output need to be dictionary format, so I just add the number as the key value.
                I'm also new to Python, so there might be a better to do this.







                share|improve this answer








                New contributor




                Willy Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                share|improve this answer



                share|improve this answer






                New contributor




                Willy Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                answered Mar 7 at 8:09









                Willy ChenWilly Chen

                11




                11




                New contributor




                Willy Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.





                New contributor





                Willy Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                Willy Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.





























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