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How to assign same key to all value in list in python3
2019 Community Moderator Electionwhat is the best way to calculate the power of several ints in a list using python3?append list values to a dictionaryIterating through dictionary with nested lists and printing at board positionSum up the second value from one dictionary with all values from another dictionaryComparing 2 dictionaries in python and create a list with values from dictionaryAppending values to existing keys in a dictionaryPython list-dictionary algorithm with big dataSorting a list based on another shorter list with incomplete valuesPython 3.6. Get average Y for all same X coordinatesBeautifulSoup4 scrapping: Pandas “arrays must all be same length” when exporting data to csv
I have two lists with the same length one contains integer values and another string.a = [4, 8, 13, 24, 35, 56]
b = ['acb','cde','efg','hij','klm','nop']
I want to make dictionary like this:dictionary = 'number':4,'name':'abc', 'number':8,'name':'cde', 'number':13,'name':'efg', 'number':24,'name':'hij', 'number':35,'name':'klm', 'number':56,'name':'nop'
the key should be the same for all the value. Thank in advance
python-3.6
add a comment |
I have two lists with the same length one contains integer values and another string.a = [4, 8, 13, 24, 35, 56]
b = ['acb','cde','efg','hij','klm','nop']
I want to make dictionary like this:dictionary = 'number':4,'name':'abc', 'number':8,'name':'cde', 'number':13,'name':'efg', 'number':24,'name':'hij', 'number':35,'name':'klm', 'number':56,'name':'nop'
the key should be the same for all the value. Thank in advance
python-3.6
add a comment |
I have two lists with the same length one contains integer values and another string.a = [4, 8, 13, 24, 35, 56]
b = ['acb','cde','efg','hij','klm','nop']
I want to make dictionary like this:dictionary = 'number':4,'name':'abc', 'number':8,'name':'cde', 'number':13,'name':'efg', 'number':24,'name':'hij', 'number':35,'name':'klm', 'number':56,'name':'nop'
the key should be the same for all the value. Thank in advance
python-3.6
I have two lists with the same length one contains integer values and another string.a = [4, 8, 13, 24, 35, 56]
b = ['acb','cde','efg','hij','klm','nop']
I want to make dictionary like this:dictionary = 'number':4,'name':'abc', 'number':8,'name':'cde', 'number':13,'name':'efg', 'number':24,'name':'hij', 'number':35,'name':'klm', 'number':56,'name':'nop'
the key should be the same for all the value. Thank in advance
python-3.6
python-3.6
asked Mar 7 at 7:55
Manohar SonwanManohar Sonwan
34
34
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I'm not sure if this is the method you want, please check the following.
a = [4, 8, 13, 24, 35, 56]
b = ['acb','cde','efg','hij','klm','nop']
c = zip(a,b)
final_dic = dict()
for i,a in enumerate(c):
temp=dict(number=a[0],name=a[1])
final_dic[i]=temp
print(final_dic)
Since the output need to be dictionary format, so I just add the number as the key value.
I'm also new to Python, so there might be a better to do this.
New contributor
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I'm not sure if this is the method you want, please check the following.
a = [4, 8, 13, 24, 35, 56]
b = ['acb','cde','efg','hij','klm','nop']
c = zip(a,b)
final_dic = dict()
for i,a in enumerate(c):
temp=dict(number=a[0],name=a[1])
final_dic[i]=temp
print(final_dic)
Since the output need to be dictionary format, so I just add the number as the key value.
I'm also new to Python, so there might be a better to do this.
New contributor
add a comment |
I'm not sure if this is the method you want, please check the following.
a = [4, 8, 13, 24, 35, 56]
b = ['acb','cde','efg','hij','klm','nop']
c = zip(a,b)
final_dic = dict()
for i,a in enumerate(c):
temp=dict(number=a[0],name=a[1])
final_dic[i]=temp
print(final_dic)
Since the output need to be dictionary format, so I just add the number as the key value.
I'm also new to Python, so there might be a better to do this.
New contributor
add a comment |
I'm not sure if this is the method you want, please check the following.
a = [4, 8, 13, 24, 35, 56]
b = ['acb','cde','efg','hij','klm','nop']
c = zip(a,b)
final_dic = dict()
for i,a in enumerate(c):
temp=dict(number=a[0],name=a[1])
final_dic[i]=temp
print(final_dic)
Since the output need to be dictionary format, so I just add the number as the key value.
I'm also new to Python, so there might be a better to do this.
New contributor
I'm not sure if this is the method you want, please check the following.
a = [4, 8, 13, 24, 35, 56]
b = ['acb','cde','efg','hij','klm','nop']
c = zip(a,b)
final_dic = dict()
for i,a in enumerate(c):
temp=dict(number=a[0],name=a[1])
final_dic[i]=temp
print(final_dic)
Since the output need to be dictionary format, so I just add the number as the key value.
I'm also new to Python, so there might be a better to do this.
New contributor
New contributor
answered Mar 7 at 8:09
Willy ChenWilly Chen
11
11
New contributor
New contributor
add a comment |
add a comment |
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