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Error 'A value of type 'dynamic' can't be assigned to a variable of type 'String'.' in Dart 2.2



2019 Community Moderator ElectionIn C#, why is String a reference type that behaves like a value type?What's the rationale for null terminated strings?How to check if type of a variable is string?dart extend string type for type checkingAssign strings from a string array to various string variablesWhy are incorrect type assignments allowed in Dart?Target type of existing array-value doesn't match the new one (dynamic)'Invalid override. The type isn't a subtype' when implementing an interfaceFlutter Future<dynamic> vs. Future<String> subtype error?how can i do dynamic casting of a variable from one type to another in Scala










0















since the last dart update (2.2)
I'm getting this error,




'A value of type 'dynamic' can't be assigned to a variable of type
'String'.'




which doesn't make much sense to me.
the code is absolutely trivial:



 class EmployeeMirror 
EmployeeMirror(this.id, this.name);

EmployeeMirror.fromMap(Map<String, dynamic> _map)
id = _map['id']; // error here
name = _map['name']; // and here


int id;
String name;



I don't think is relevant, but this is in an Aqueduct project.



thanks in advance for the help










share|improve this question

















  • 1





    You can disable this check by removing implicit-cast: false (or setting it to true) from the analysis.options.yaml file. dartlang.org/guides/language/…

    – Mattia
    Mar 7 at 14:46
















0















since the last dart update (2.2)
I'm getting this error,




'A value of type 'dynamic' can't be assigned to a variable of type
'String'.'




which doesn't make much sense to me.
the code is absolutely trivial:



 class EmployeeMirror 
EmployeeMirror(this.id, this.name);

EmployeeMirror.fromMap(Map<String, dynamic> _map)
id = _map['id']; // error here
name = _map['name']; // and here


int id;
String name;



I don't think is relevant, but this is in an Aqueduct project.



thanks in advance for the help










share|improve this question

















  • 1





    You can disable this check by removing implicit-cast: false (or setting it to true) from the analysis.options.yaml file. dartlang.org/guides/language/…

    – Mattia
    Mar 7 at 14:46














0












0








0








since the last dart update (2.2)
I'm getting this error,




'A value of type 'dynamic' can't be assigned to a variable of type
'String'.'




which doesn't make much sense to me.
the code is absolutely trivial:



 class EmployeeMirror 
EmployeeMirror(this.id, this.name);

EmployeeMirror.fromMap(Map<String, dynamic> _map)
id = _map['id']; // error here
name = _map['name']; // and here


int id;
String name;



I don't think is relevant, but this is in an Aqueduct project.



thanks in advance for the help










share|improve this question














since the last dart update (2.2)
I'm getting this error,




'A value of type 'dynamic' can't be assigned to a variable of type
'String'.'




which doesn't make much sense to me.
the code is absolutely trivial:



 class EmployeeMirror 
EmployeeMirror(this.id, this.name);

EmployeeMirror.fromMap(Map<String, dynamic> _map)
id = _map['id']; // error here
name = _map['name']; // and here


int id;
String name;



I don't think is relevant, but this is in an Aqueduct project.



thanks in advance for the help







string dynamic dart aqueduct






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 7 at 7:54









Francesco IapiccaFrancesco Iapicca

889




889







  • 1





    You can disable this check by removing implicit-cast: false (or setting it to true) from the analysis.options.yaml file. dartlang.org/guides/language/…

    – Mattia
    Mar 7 at 14:46













  • 1





    You can disable this check by removing implicit-cast: false (or setting it to true) from the analysis.options.yaml file. dartlang.org/guides/language/…

    – Mattia
    Mar 7 at 14:46








1




1





You can disable this check by removing implicit-cast: false (or setting it to true) from the analysis.options.yaml file. dartlang.org/guides/language/…

– Mattia
Mar 7 at 14:46






You can disable this check by removing implicit-cast: false (or setting it to true) from the analysis.options.yaml file. dartlang.org/guides/language/…

– Mattia
Mar 7 at 14:46













1 Answer
1






active

oldest

votes


















1














class EmployeeMirror 
EmployeeMirror(this.id, this.name);

EmployeeMirror.fromMap(Map<String, dynamic> _map)
id = _map['id'] as int;
name = _map['name'] as String;


int id;
String name;






share|improve this answer























  • wow that was easy, thanks :)

    – Francesco Iapicca
    Mar 7 at 8:48










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1 Answer
1






active

oldest

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1 Answer
1






active

oldest

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active

oldest

votes






active

oldest

votes









1














class EmployeeMirror 
EmployeeMirror(this.id, this.name);

EmployeeMirror.fromMap(Map<String, dynamic> _map)
id = _map['id'] as int;
name = _map['name'] as String;


int id;
String name;






share|improve this answer























  • wow that was easy, thanks :)

    – Francesco Iapicca
    Mar 7 at 8:48















1














class EmployeeMirror 
EmployeeMirror(this.id, this.name);

EmployeeMirror.fromMap(Map<String, dynamic> _map)
id = _map['id'] as int;
name = _map['name'] as String;


int id;
String name;






share|improve this answer























  • wow that was easy, thanks :)

    – Francesco Iapicca
    Mar 7 at 8:48













1












1








1







class EmployeeMirror 
EmployeeMirror(this.id, this.name);

EmployeeMirror.fromMap(Map<String, dynamic> _map)
id = _map['id'] as int;
name = _map['name'] as String;


int id;
String name;






share|improve this answer













class EmployeeMirror 
EmployeeMirror(this.id, this.name);

EmployeeMirror.fromMap(Map<String, dynamic> _map)
id = _map['id'] as int;
name = _map['name'] as String;


int id;
String name;







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 7 at 8:41









mezonimezoni

4,10921531




4,10921531












  • wow that was easy, thanks :)

    – Francesco Iapicca
    Mar 7 at 8:48

















  • wow that was easy, thanks :)

    – Francesco Iapicca
    Mar 7 at 8:48
















wow that was easy, thanks :)

– Francesco Iapicca
Mar 7 at 8:48





wow that was easy, thanks :)

– Francesco Iapicca
Mar 7 at 8:48



















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